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      "author": "dangen",
      "permlink": "3gsxbg-1",
      "title": "채점하기 - 제1회 구름코드챌린지 기출 문제",
      "body": "![algorithm.png](https://cdn.steemitimages.com/DQmTrJUNvjEBuasqSwNYhkhRDjLHVDKpsqkgTxDymuxZZZG/algorithm.png)\n\n## 문제 ##\n<br/>\n\n중학교 선생님인 구름이는 자신이 출제한 기말고사 문제를 채점하는 중 입니다. \n\n문제마다 ```o``` 또는 ```x``` 표시가 되어있는데 점수를 매기는 방식이 특이합니다.\n\n```o```는 점수가 누적되는 방식으로 채점되는데 이전부터 자신을 포함한 연속된 ```o```의 개수 만큼의 점수로 채점이 됩니다.\n\n예를 들면 ```oooxoo```가 있다면 순서대로 ```1 + 2 + 3 + 0 + 1 + 2 = 9```점이 되겠습니다.\n\n학생이 푼 시험지에 정답, 오답 여부가 표시되어있을 때 총점을 구하는 프로그램을 작성하여 구름이를 도와주세요.\n\n[출처](https://edu.goorm.io/learn/lecture/790/%EC%A0%9C1%ED%9A%8C-%EA%B5%AC%EB%A6%84%EC%BD%94%EB%93%9C%EC%B1%8C%EB%A6%B0%EC%A7%80-gcc-%EA%B8%B0%EC%B6%9C-%EB%AC%B8%EC%A0%9C/lesson/29969/%EC%B1%84%EC%A0%90%ED%95%98%EA%B8%B0) - 구름\n\n<hr/>\n\n## 풀이 ##\n<br/>\n\n1. 주어진 문자열 길이만큼 순회합니다.\n\n2. ```i 번째 캐릭터```의 값을 검사합니다.\n\n3. ```o``` 라면 보너스 점수를 증가시키고 총점에 합산합니다.\n\n4. ```x```  라면 보너스 점수를 ```0```으로 초기화합니다.\n\n```java\npublic class Hello {\n    public static void main(String[] args) {\n        String str = \"oooxoo\";\n        int bonus = 0;  // 보너스 점수를 누적 시킴\n        int sum = 0;    // 총점\n\n        for (int i = 0; i < str.length(); i++) {\n            // case: 'o'\n            if (str.charAt(i) == 'o') {\n                bonus++;        // 보너스 점수 증가 \n                sum += bonus;   // 총점 증가\n            }\n            // case: 'x'\n            else {\n                bonus = 0;      // 보너스 점수 0으로 초기화\n            }\n        }\n        \n        System.out.println(sum);    // 결과 출력\n    }\n}\n```\n<br/>\n\n```console\n> java Hello\n9\n```\n<br/>",
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      "title": "팰린드롬(Palindrome) 문제",
      "body": "![algorithm.png](https://cdn.steemitimages.com/DQmTrJUNvjEBuasqSwNYhkhRDjLHVDKpsqkgTxDymuxZZZG/algorithm.png)\n\n## 문제 ##\n<br/>\n\n팰린드롬은 거꾸로 읽어도, 바르게 읽어도 똑같은 문장입니다.\n\n예를들어\n\n* level 팰린드롬입니다.\n* star 팰린드롬이 아닙니다.\n\n주어진 문자열이 팰린드롬인지 출력하세요.\n\n- - -\n\n## 풀이 ##\n<br/>\n\n1. 길이가 n 인 문자열을 입력합니다.\n\n2. 문자열의 ```첫번째, n 번째 캐릭터```가 같은지 검사합니다.\n\n3. 문자열의 ```첫번째 + 1, n 번째 - 1  캐릭터```가 같은지 검사합니다.\n\n4. 문자열의 ```첫번째 + 2, n 번째 - 2  캐릭터```가 같은지 검사합니다.\n\n5. 반복합니다.\n\n```java\npublic class Hello {\n    public static void main(String[] args) {\n        String str = \"level\"; // 팰린드롬 문자열\n        boolean isPalindrome = false;\n        int center = str.length() / 2;\n        int last = str.length() - 1;\n\n        for (int start = 0; start < center; start++) {\n            // 격차를 줄여가며 처음과 끝의 캐릭터가 같은지 검사\n            if (str.charAt(start) == str.charAt(last - start)) {\n                isPalindrome = true;\n            } else {\n                isPalindrome = false;\n            }\n        }\n\n        // 결과 확인\n        System.out.println(isPalindrome);\n    }\n}\n```\n<br/>\n\n```console\n> java Hello\ntrue\n```\n<br/>",
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